 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
+ `/ e0 j6 W% @8 V
3 D" y r9 j7 H. t5 ^" T 1# jack_lai * h( Y( \4 |/ U) K+ J
; C3 |2 F) K+ z6 H0 X1 T1 \ P足球看完了来看看题目。
6 Q+ u: A% Z( b- L$ C f5 o. S- C7 \/ _" k
The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
, B4 w0 u& C( w& MThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different): y/ O/ w; s2 L t
We can see it is not easy to install the 22 meters heat trace according as figure 1( x$ H _- I9 |. j
# T6 g0 T( c4 P4 u# Q
/ D1 [' i1 u5 Z7 U9 p, N2 B
2 [! A, u' a2 Y, A& C, W U N4 l: p) T
% d: g" X& C7 B2 n* iAs a normal question we just discuss:" b5 R* o" P* w. N" L& p3 Y6 z
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
# }1 f; V: R* g y! XI call this is JACK LAI Spiral Method 螺旋法
/ N% Q$ d: ~& RThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.! R/ G0 m! a/ R; K4 a4 ]
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
) t" ~- d H; j* F0 }2 _4 E6 I( l0 ]Because the pipe is horizontal, position 0 can not be placed. See figure 20 {: X7 m- U+ i( ]5 G( Q: |% g
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 35 a3 p" }- ~. W( B7 E" r2 l
The total heat trace that can be installed here is about ; I \. I, m! y. _% c& O% y
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters( a! s1 u9 _5 w5 K6 b
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
& h; Z9 t9 m# F: H6 [5 t8 S* ~7 Q; `$ ` f
Note :
# j$ L% a8 P7 ~8 A \2 N! x' ^, _2 Z1. The minimum bend radius:, \: P; r8 T" Y8 C, Z3 G) B% O
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is& S3 R% `7 J) V* _
5/16 *6 = 30/16 almost = 2 inches7 f( O+ l* e, [# G$ V
So the maximum bend radius is 2 inches.$ u3 {; n; M6 s% B0 [
4 U8 d3 e3 H! V8 W9 n% A
( A: F$ r" h, P& O6 n1 c( S6 X; W* p* @9 {, c/ A- D6 W, X/ x- O
Summary
1 L. ?7 I) t. @1 V; fAs regular
% B! m7 E! j# p9 ^; x3 WFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe+ j7 ]8 ~: q5 `# J9 D/ f5 @( k, t
if the pipe is horizontal, The length of heat trace can be installed is about) u# F" d8 M) B( x# F
1 * 9 = 9 meters" ^4 Z0 |* H$ |+ |
If the pipe is vertical, The length of heat trace can be installed is about* m7 L$ t3 G2 F) z: W" k. [
1 * 10 = 10 meters.
+ O3 ]! L5 Y2 HFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe: h4 L. U) f# Z. T- ?
if the pipe is horizontal , The length of heat trace can be installed is about' z7 A3 y6 U9 ]2 v7 c
1 * 4 = 4 meters, ~' |' j8 ^; k. f
If the pipe is vertical, The length of heat trace can be installed is about s, ~% u: ~- d
1 * 5 = 5 meters. |
|