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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。
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+ z( m/ @5 A# M0 r, dThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7) n6 V. U4 k0 g: B
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
5 W8 k( U5 l3 N+ E sWe can see it is not easy to install the 22 meters heat trace according as figure 1
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/ ^" }3 [' f4 _" Z0 IAs a normal question we just discuss:: J0 O; I& a1 B/ |
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? / g) h/ ] A7 z1 X
I call this is JACK LAI Spiral Method 螺旋法
) a$ C- A8 I TThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
4 k2 p* p. @ s' [2 Z; dThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. : p, ]2 n, |4 P, H; G1 ]3 P$ Z
Because the pipe is horizontal, position 0 can not be placed. See figure 2
8 o& f$ @% w, p/ l. d3 MBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 39 z5 H% D5 m8 M
The total heat trace that can be installed here is about
0 e+ b+ h1 v" _+ U, D( W% I4 z1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
2 F k& _/ \1 P3 zSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. % j9 S; b0 R% n1 b. c! t4 P0 P5 _ V
; }! C O# ^# |4 g, R7 x- jNote :
! T- m* Y3 r; n6 X+ B, d. G9 W& v1. The minimum bend radius:0 J& R/ S6 E% e$ x8 Q' F9 P
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is8 v5 O m5 O# l1 `; C$ ~: Q
5/16 *6 = 30/16 almost = 2 inches
! p3 ?. r' c9 L" U: l USo the maximum bend radius is 2 inches.# i& G, r- X% X# O8 ?3 b) v) }
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7 _% |& Q- \' n$ G8 Q! z2 USummary
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! G( L) G+ v, m) n; UFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe+ z( Y! |& H; ^; ~6 y
if the pipe is horizontal, The length of heat trace can be installed is about
7 u8 r9 s# E; F4 O2 b. N* E8 y1 * 9 = 9 meters( h$ _1 ? A$ s- h
If the pipe is vertical, The length of heat trace can be installed is about
0 B! r: T3 H, ?, l, q0 \7 }1 * 10 = 10 meters.
2 H4 J( G" ?; rFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe- ^* {; Q$ J) U/ D' }9 b
if the pipe is horizontal , The length of heat trace can be installed is about
" w$ x; W$ m, k' c5 B f3 ]. }! v1 * 4 = 4 meters
- Q- a- ?8 }$ b* i* I0 RIf the pipe is vertical, The length of heat trace can be installed is about
9 u4 y1 m7 `' f3 H) E1 * 5 = 5 meters. |
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