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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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1# jack_lai
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足球看完了来看看题目。
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)6 }0 Q0 Z( _- p0 W& d; R$ S
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)) u6 W' m T7 l9 y+ k" z s, g9 ~
We can see it is not easy to install the 22 meters heat trace according as figure 10 H; Z/ Y' U% K" \
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4 R+ |9 }* [8 H4 u1 @+ b$ t, [+ vAs a normal question we just discuss:
/ @9 j, Y1 a2 V8 @2 \9 k% V* LHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
3 t) }+ X" _' }# |8 J1 n1 B) |I call this is JACK LAI Spiral Method 螺旋法
7 S7 u+ p* v, lThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.) `5 P! Z+ c' d5 [1 C4 h4 G
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
9 T R d& N; K8 R' Z. s! }9 j9 kBecause the pipe is horizontal, position 0 can not be placed. See figure 2- W" U- A3 B) z9 }. \
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
7 p" d# b6 c4 a* o; J5 I/ zThe total heat trace that can be installed here is about * R3 y5 Y* E" L3 P( I
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters& J) Y( t# ? ]) t. G
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 2 X* v) a3 F3 j, f
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Note :
7 J0 A7 g6 X5 |- O/ f& P1. The minimum bend radius:
7 a" j5 F" x# _ I( P! V4 ~% VBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
/ A2 w, P) Y% t5/16 *6 = 30/16 almost = 2 inches: i! y" F. B* `; n# U* \# S2 p4 D9 J
So the maximum bend radius is 2 inches.
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Summary+ D! c. i6 D6 a
As regular
3 A5 w1 J" s( G( ?- d- W2 j$ gFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
) C7 ]* J$ T Uif the pipe is horizontal, The length of heat trace can be installed is about2 X5 [) k" ], y/ U, c
1 * 9 = 9 meters' U# x3 k& e1 A; Q& h) F1 }. Z
If the pipe is vertical, The length of heat trace can be installed is about
8 F* j6 B E9 R+ E& M1 * 10 = 10 meters.
; O; F) ]* T+ V$ [) zFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe: n9 g7 y# y6 }; p: b
if the pipe is horizontal , The length of heat trace can be installed is about
, e" s( ]- A7 u' t2 `1 H1 * 4 = 4 meters% N: v7 h: h3 J1 \, t y7 y
If the pipe is vertical, The length of heat trace can be installed is about
- G) h8 [ ~( I3 y) x1 * 5 = 5 meters. |
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