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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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1# jack_lai
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1 r& K+ N h" N8 X足球看完了来看看题目。
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! p4 w/ x% e' W8 H) o) Z5 n8 YThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
, h' o7 E. c4 D) Q9 hThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
: n" N. ]7 j6 y1 ^* D' s6 z+ GWe can see it is not easy to install the 22 meters heat trace according as figure 1
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: J$ K# Y5 k8 S( K! ^+ w" s- }As a normal question we just discuss:: G$ N! X' [6 t6 S, M+ b
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
6 [/ U0 k) ]* m: d' N" A: j- I# LI call this is JACK LAI Spiral Method 螺旋法1 }& e7 }& ?0 g9 L& c0 u
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.5 U9 l9 @4 u1 S/ |) c
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. / l, U8 D& K3 o( ^+ @; J
Because the pipe is horizontal, position 0 can not be placed. See figure 21 @' C# p7 S) `( t( z! n. x5 o5 D
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3* |/ Q# \. o* |" t6 ~# K5 o3 u
The total heat trace that can be installed here is about * x* |# R( a) i3 z8 |9 j* Y: L
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters, R; d! k6 H8 F0 f: _3 B# A
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. . L% l! `. K7 {4 {0 j$ A( |
% t$ K8 K+ d% Z6 O" pNote :
9 _$ e: w; _4 i; G; {: m1. The minimum bend radius:
$ C* p |% s' |Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is) m! H+ V! ?9 ?
5/16 *6 = 30/16 almost = 2 inches( V: d3 M9 l r
So the maximum bend radius is 2 inches.4 d a6 ]: \2 w! H% q! ~# ]
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Summary
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+ l5 W0 u# l g9 xFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
7 s* j6 U }' Q) t4 P/ U5 C, a+ Eif the pipe is horizontal, The length of heat trace can be installed is about) S9 v* D$ r4 S5 {/ L
1 * 9 = 9 meters
& G4 `& S1 l$ i7 iIf the pipe is vertical, The length of heat trace can be installed is about: g1 c, D# R8 o9 q
1 * 10 = 10 meters.
, W" @8 n5 `; \$ B$ ~' @! NFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
9 e! A8 F: y7 t5 iif the pipe is horizontal , The length of heat trace can be installed is about
* l' h! p- I, y4 V1 * 4 = 4 meters
* Y' D3 e3 P. @. aIf the pipe is vertical, The length of heat trace can be installed is about b& l4 H" o0 P9 p ~# }0 |% o) i$ ?
1 * 5 = 5 meters. |
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