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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 9 a$ D! z8 I+ P( z& i7 p* d
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1# jack_lai ; h! y% j* @+ c' B2 ?4 q
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足球看完了来看看题目。
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; Q$ A1 j2 c$ ]+ |The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
7 W. V) j- O QThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
- {$ C' ?5 Q1 xWe can see it is not easy to install the 22 meters heat trace according as figure 1% j" ]# b7 O t* j3 \) k
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As a normal question we just discuss:2 C' Y6 [& p0 o5 `; L" R7 v/ p
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 6 g% E: W9 p/ p- \' F
I call this is JACK LAI Spiral Method 螺旋法* X4 H( W4 {6 a A; w4 K5 e5 _
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
* m! D `, R) K- s0 ?( t# k& EThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. - w I# p" J) ~4 _6 ?% R! a; X
Because the pipe is horizontal, position 0 can not be placed. See figure 2
5 ]6 s; X) H; bBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
f2 N& _ H- y" d# d" U" O0 EThe total heat trace that can be installed here is about
- v8 _8 X: l6 z1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
' C2 B$ P/ a$ n- L( x% VSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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Note :. h" n# i7 v8 z4 l2 q
1. The minimum bend radius:* H3 @8 s; D6 ]+ D
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is$ Q- u2 Y+ H- i" \
5/16 *6 = 30/16 almost = 2 inches
" T" u/ R- q: X1 _: _; t. U' dSo the maximum bend radius is 2 inches.
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
* G0 n! |7 f( G0 u/ F& J# w' ]: zif the pipe is horizontal, The length of heat trace can be installed is about
2 J, c& l9 ~& [% }1 * 9 = 9 meters
t- D' e3 \# V) A. L4 rIf the pipe is vertical, The length of heat trace can be installed is about8 _$ f$ E0 l0 @7 h0 _( I: c$ g
1 * 10 = 10 meters. 9 p7 L. X4 z) W' W1 O+ h; n! }) _
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe' i$ G9 { A. F$ r
if the pipe is horizontal , The length of heat trace can be installed is about0 D! D6 F; p. x. z7 ?" @: q
1 * 4 = 4 meters+ T& l/ J3 i( P2 _
If the pipe is vertical, The length of heat trace can be installed is about
$ t+ s+ h! W; Z* i1 * 5 = 5 meters. |
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