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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 : V- d+ y$ Y5 C
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足球看完了来看看题目。
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4 |9 h V ^8 C5 t( JThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
C. L, R. Z I2 ~: }) S9 L, [5 AThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)9 _8 P) a2 B/ c* I' @/ K
We can see it is not easy to install the 22 meters heat trace according as figure 1$ A1 _9 l0 {2 Q9 V
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# T0 U6 ]4 P3 @, zAs a normal question we just discuss:
3 w+ w( k7 F. KHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? , Q4 w2 l! c* A0 A/ I* P9 b0 `
I call this is JACK LAI Spiral Method 螺旋法0 Q8 y y1 h1 h4 `$ s
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
2 ]6 s _! f2 ?& w3 ]% ^7 ]There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
; ^5 d5 ~) u. N' X+ T) p$ Z8 {Because the pipe is horizontal, position 0 can not be placed. See figure 2
& k/ l3 [* s" s! b J- C) |+ vBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3' C$ n: b; H+ j3 z4 U
The total heat trace that can be installed here is about 9 ?8 Z. m4 R; S4 K" s8 ?- k
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
2 Z, z" l8 |$ x! Q0 iSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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# u3 r! F$ i! L/ I" Z3 w) U# i% qNote :
3 M$ A" u' |4 I; p( ?3 r3 c3 E1. The minimum bend radius:. G0 e% w5 x, H4 @0 u& f
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
/ X0 H2 Z b3 t" I+ _1 X4 K4 u" l5/16 *6 = 30/16 almost = 2 inches3 S) y9 g- n1 `, c
So the maximum bend radius is 2 inches.
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
7 O9 Y$ B$ k6 X+ |( Nif the pipe is horizontal, The length of heat trace can be installed is about1 L. D" {2 H8 _! D- Z* @. h# |
1 * 9 = 9 meters
* f1 d$ z4 I/ x& k1 D. [If the pipe is vertical, The length of heat trace can be installed is about
& w+ G% z' M, w+ w+ L1 * 10 = 10 meters.
) J* C0 a* W9 C# q+ FFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe% o! j5 m# o/ U" C
if the pipe is horizontal , The length of heat trace can be installed is about
* o6 ~# ` F# q, Q( R$ U1 * 4 = 4 meters
' b$ t$ n5 t2 m, M% m3 z% G# MIf the pipe is vertical, The length of heat trace can be installed is about2 c/ n& |' n0 C" s3 U. U( P
1 * 5 = 5 meters. |
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