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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 + @, V: S# B+ L% d
# ^5 C3 z9 }" m 1# jack_lai
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( ^ k: j- P$ N: O足球看完了来看看题目。9 d4 f2 Y: |; G t. [- X$ c
! ~( `+ a3 t3 X- g. LThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7); D. r' G% `* L$ u. s
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)+ p" B& R" j) m' f% g6 q
We can see it is not easy to install the 22 meters heat trace according as figure 1
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6 [# f+ }* L, [! }8 lAs a normal question we just discuss:
) q) j) n5 _0 `9 N/ vHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
+ v- {) r6 U4 M* O# nI call this is JACK LAI Spiral Method 螺旋法1 u3 F+ h) v. R& G9 j5 k, }
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2./ ^1 S; }) R9 p4 c4 O2 v
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. & q" v0 s( F7 y3 v- c0 Y
Because the pipe is horizontal, position 0 can not be placed. See figure 2, [ a) ^& \' p' M( h! j) I+ H
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 39 t9 L- t* u7 P( _
The total heat trace that can be installed here is about
" L9 g V, C, Y4 J7 e1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters% P, e3 D4 O8 c" N
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. & S3 G5 _' I+ v
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Note :
8 @2 p$ {# C0 ?1. The minimum bend radius:
: K* i4 X- J3 K4 DBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is, n6 g" l( ]. o' B U* F# Q3 V
5/16 *6 = 30/16 almost = 2 inches
. Y: ~& M5 P# c3 qSo the maximum bend radius is 2 inches.6 ~5 g& J0 q0 \- [
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7 S. C* e7 M! l. H5 _Summary
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1 h9 r5 l' F& O1 K& y6 {For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe" k0 |5 {8 x' g( y6 Q
if the pipe is horizontal, The length of heat trace can be installed is about
- x0 \0 X9 x* v! M1 * 9 = 9 meters
/ q4 T0 r, ` Y `If the pipe is vertical, The length of heat trace can be installed is about
2 y) O% u V& F% B1 * 10 = 10 meters.
) i* `' {( \( \1 z- Y2 x2 ~$ }For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
* @: A2 ~$ T4 H4 M ]$ N" b$ D2 qif the pipe is horizontal , The length of heat trace can be installed is about' X1 l6 |8 T9 K
1 * 4 = 4 meters" K' e, h4 f' C5 Z9 K
If the pipe is vertical, The length of heat trace can be installed is about
6 a4 ^* C6 I5 k V4 i7 R1 * 5 = 5 meters. |
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