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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 - }) {1 i' T; h7 U# e
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足球看完了来看看题目。/ l) a& E8 E+ f
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
2 s, y5 ^! q: w6 ]2 j' wThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)# p+ g2 _% }8 ^5 d; {. s; ?, y3 X
We can see it is not easy to install the 22 meters heat trace according as figure 1
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* P3 S* \* z. f8 z+ ^As a normal question we just discuss:
" @. t8 J" l7 t( S r' Z: R1 WHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
$ ], n; v( ~; c% w) cI call this is JACK LAI Spiral Method 螺旋法
; |" V9 o; @2 oThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.0 Y4 |$ D4 f( g8 I8 F, T9 c& K
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
' q6 m/ [, {- V# Y l) b gBecause the pipe is horizontal, position 0 can not be placed. See figure 21 C! j2 m4 o/ c( ^6 A# }
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3 M$ }+ f+ F9 \9 H+ K+ b5 ^
The total heat trace that can be installed here is about
8 f$ ^- h) H- e: M _+ s1 {% M7 r# N: ]1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
% C5 a% K! G+ eSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. . |8 ]) p& e/ e/ ^: F, O
0 d2 O# o1 u; G: |6 ^/ x/ u& sNote :, ? K; g w# S: U# l' ~' R1 w0 Z
1. The minimum bend radius:- a! f4 J- k1 u+ `2 u8 a7 K
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is( O: |) q K3 m7 i+ T b3 q% T
5/16 *6 = 30/16 almost = 2 inches2 f# P2 M( R# y- Z5 _3 O: U$ E
So the maximum bend radius is 2 inches.( g) N: H7 D5 t/ u7 \
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Summary
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5 t/ o# m: c$ wFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
$ J1 z4 i/ H# G" B. f3 I: q% Vif the pipe is horizontal, The length of heat trace can be installed is about
7 ]" k. Z: R. C/ \; B( Z* v1 * 9 = 9 meters
; T M C0 I* X5 d c. z/ yIf the pipe is vertical, The length of heat trace can be installed is about
! D; `- {! f9 j- k) {& R4 f1 * 10 = 10 meters. ; S/ }0 r! H: V" I: N
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
. s! A& V# A0 ^) H( T0 m2 Pif the pipe is horizontal , The length of heat trace can be installed is about
9 u. F7 u+ M$ D& A# j' I1 * 4 = 4 meters
! p) p! t4 d/ q. w6 uIf the pipe is vertical, The length of heat trace can be installed is about6 V, @+ } Q. X
1 * 5 = 5 meters. |
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