 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 1 g& G. t% [ y8 v7 v( Z, e
; R- h! _6 y# k2 T
1# jack_lai , N* |) A: n8 N! c/ q3 B. ?
% d T5 k- C! u! Y$ m& k0 @足球看完了来看看题目。
5 k; P; R0 u& L3 C8 f8 t, x7 b8 `9 L) Y4 L$ _& Q
The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
, P( A& b1 l; P% xThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
- T' {" E! b7 nWe can see it is not easy to install the 22 meters heat trace according as figure 1
6 V/ r% u' X! l: P( S2 `# @& P, f
) d$ l8 } g9 u* o: J% p& A
4 \0 @% f& [: a/ @
4 n) N# p# j( W! c+ ]2 I. C! e1 o8 j- L
As a normal question we just discuss:
! w' a( l5 M- L6 nHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? \/ f0 l. j" b) @( E' g
I call this is JACK LAI Spiral Method 螺旋法, F3 U* w4 u# \+ m7 G& Q! i! T
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.9 t. G; E4 W8 i; b: _2 r* U
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
* l- V9 \& \( p/ K5 T3 Q4 X, EBecause the pipe is horizontal, position 0 can not be placed. See figure 2
8 N6 I' z$ D7 \1 h( F5 O" V, gBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3: N( h5 L4 x9 E" e) i& h4 n
The total heat trace that can be installed here is about
: z+ S R6 \( {8 j7 A1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
1 K% ~, I7 _# L) A) @So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. + z; e) g8 r" Y, y* y* R4 k" p2 U
5 i+ n/ w, j* W: ^: I LNote :, R. F6 O7 m' I* c# E
1. The minimum bend radius:- ^( ?8 p4 ?- O1 ^; X7 m
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
: j: B5 @3 W s2 m5/16 *6 = 30/16 almost = 2 inches
/ U+ Z+ A" N/ N% C Q2 K A7 ?So the maximum bend radius is 2 inches.7 r0 G5 I# r" L8 m1 c9 `, {/ v
8 ~8 m% u+ v; V# u
3 S7 y3 \: j/ L) e' B( k2 c' \) j8 Z
r& H; \) Z I' m
Summary
0 u% q: Q2 y/ S9 c- n6 DAs regular 0 e: a, a. @4 a1 v ^' e' T+ A& N, U U
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe: l; L1 e+ v/ [% b' [ {
if the pipe is horizontal, The length of heat trace can be installed is about# N. c* f) L. u/ I" r
1 * 9 = 9 meters% P4 i, m9 F) _1 N- ~" |
If the pipe is vertical, The length of heat trace can be installed is about
: P. M% \) V8 C/ X! B8 w- K+ { M1 * 10 = 10 meters. `. j9 _& C! A2 Q: Z% F
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe; |: i# r* m. S0 C
if the pipe is horizontal , The length of heat trace can be installed is about
" W8 E- j* V4 [+ e i1 * 4 = 4 meters
& K5 W( D9 K( c6 P5 d. X$ ?If the pipe is vertical, The length of heat trace can be installed is about
" W, T% C, A' T& \; z) S1 * 5 = 5 meters. |
|