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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 , t( H! ?5 z' h8 A! }1 ~
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# [( _, `# z: s- [+ [足球看完了来看看题目。$ V$ ?. o _5 d8 ?
6 l/ _ ]: R* i' y5 ?The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)' a3 n C y+ `' ?
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
6 f# Y8 V% v% P( M+ o6 ~3 p {We can see it is not easy to install the 22 meters heat trace according as figure 1
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; q( Y; j. P) A, M' |1 NAs a normal question we just discuss:3 M2 x; @4 s: y, f, _ p
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
* ?3 ^' h* p, T2 K, vI call this is JACK LAI Spiral Method 螺旋法( {9 m8 ^7 \! X# G0 V3 \
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.. m3 i1 e; H9 z2 G5 c. Q( \2 [/ t
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. & v* Y7 k; p, n- Y5 G( g5 o/ E8 f
Because the pipe is horizontal, position 0 can not be placed. See figure 21 S9 X7 h! M, _8 i$ L3 r$ s1 d
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3( V0 a: V: S. X8 P) G% @0 x
The total heat trace that can be installed here is about
5 H {& `& P1 J o1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
' ~, f3 G) y# [! [6 h* u [So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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; g7 @. o' s1 d- n; z8 QNote :7 I' T& g; z$ W4 v. E) T& |$ s
1. The minimum bend radius:8 r* t3 X+ n* k9 S7 s+ U* d$ X J
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
) n8 P4 F$ B3 D7 p, f5/16 *6 = 30/16 almost = 2 inches
$ R( z8 f. z9 ^0 c3 e9 h+ l( Q4 KSo the maximum bend radius is 2 inches.
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
) k, w+ |- j$ G4 L6 X) }if the pipe is horizontal, The length of heat trace can be installed is about; s: | ^3 V" w8 D; z, O
1 * 9 = 9 meters( ^" g( E8 S6 D8 ^ a8 z$ x
If the pipe is vertical, The length of heat trace can be installed is about
, L$ v8 B8 W1 A" Z1 d- Z. L1 * 10 = 10 meters.
4 W6 E6 v( ^+ ^. KFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
8 P! Y9 w4 n4 M! n- L r8 k) ^if the pipe is horizontal , The length of heat trace can be installed is about
0 c1 P/ _) I) n- q2 E1 * 4 = 4 meters' J% e; Y5 M, E, u/ a4 I% U3 c
If the pipe is vertical, The length of heat trace can be installed is about2 z2 \" I, [$ F: S
1 * 5 = 5 meters. |
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