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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 6 H7 ], L% h7 P3 L4 V9 W
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1# jack_lai
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足球看完了来看看题目。
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" h0 K$ y1 D) n! a) EThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
- w9 U! v9 k! i6 u+ R9 A* MThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
: [1 ^1 ^* e& R% `2 T+ XWe can see it is not easy to install the 22 meters heat trace according as figure 1: q* p5 u+ V+ q5 z- x, h7 _
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# d+ P' L+ C, _# H) NAs a normal question we just discuss:
7 H+ M4 W) F; k+ X+ ?! IHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 8 e8 e k5 g: C2 @" L% G3 H
I call this is JACK LAI Spiral Method 螺旋法
6 ^" d d9 ~2 G. [The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2." [7 ?6 M9 Z7 {1 p4 L) L( Z
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 0 i. T A% n8 R0 `2 I
Because the pipe is horizontal, position 0 can not be placed. See figure 2
4 T0 U: O) G) GBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3 o+ o* z& B# u# O g4 k, Z7 s
The total heat trace that can be installed here is about ( b; ?6 n0 B; `' D# n' e
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters1 s: g7 U/ a: E: ~3 K9 N$ J4 z
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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7 E. k' C' S6 O# `; WNote :
6 k$ m; R+ @& `! P0 w }1 y9 E$ K* t' `1. The minimum bend radius:
% }( z( R) ]- b- b( h% hBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
* ^& Z" x' d7 f& E' c o5/16 *6 = 30/16 almost = 2 inches
+ b K% I3 S4 E# ESo the maximum bend radius is 2 inches.1 d! b2 ?7 d' _6 e1 s( e$ z' W- m+ E' t
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As regular 2 W3 [7 D1 \! _/ j# [! k4 h) |
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
) H. `! W% m+ B8 q# sif the pipe is horizontal, The length of heat trace can be installed is about( J0 s# m# \1 a7 j( S- o) ^" j
1 * 9 = 9 meters
* G6 B9 C7 \+ |2 r# DIf the pipe is vertical, The length of heat trace can be installed is about
$ O: u% T: W2 @( n: V1 * 10 = 10 meters.
: i" d: K: _4 @, w! z8 \/ ]! [For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe) c. I. O3 y+ `7 I2 c
if the pipe is horizontal , The length of heat trace can be installed is about. k- U& z( ]$ O+ Q
1 * 4 = 4 meters+ e+ q, B# g+ V
If the pipe is vertical, The length of heat trace can be installed is about
* \0 E5 P# P9 |! [- y5 X( ~1 * 5 = 5 meters. |
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