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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。
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3 C2 T! Z2 h4 v( M0 i$ }# yThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)$ p/ @7 V2 X; U8 y1 E& D- d1 q
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)1 F& H7 G5 G6 z! {5 ~
We can see it is not easy to install the 22 meters heat trace according as figure 1% t$ K; B9 k5 h$ t
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) y+ Z% P% K* b6 f6 P5 R3 t6 {9 e b0 IAs a normal question we just discuss:: a( s1 P1 k0 k" o+ Y4 w: _6 P
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
! I! g# f/ P% d$ g GI call this is JACK LAI Spiral Method 螺旋法 w$ f* X$ i* F; O9 k
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.' ~' R& ~. b5 c9 H" R4 |' {5 O) C
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 9 ~( H# x; s* {
Because the pipe is horizontal, position 0 can not be placed. See figure 2
/ ]- O" _5 z; r& L3 C, TBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
* H6 ^1 A8 F9 }1 [. \, l% ]The total heat trace that can be installed here is about
' x2 F. S, Z. v0 J j1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
8 D! F+ L' ]7 p! A: ]* \. `7 f. rSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 8 W* L; h8 Q. W2 ~' b ^% A
- G* R X5 n' ~ f" Y% i* Z* K2 lNote :* T9 y+ I* {( q0 M o9 k8 E
1. The minimum bend radius:, v6 r1 f5 B+ g5 d, M! f, {; {6 w, E
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is6 L$ R; q" j, J. x7 h8 r5 x
5/16 *6 = 30/16 almost = 2 inches
& M! v; Z4 t! K6 F) I; P2 f, a. LSo the maximum bend radius is 2 inches.: w' }7 G* W8 K
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! G' b5 }+ j2 }$ Q% ?2 bFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
' n. Q' y. s$ R; `5 z2 Y1 f! pif the pipe is horizontal, The length of heat trace can be installed is about' R# \0 \1 c% c4 o: m5 _; W$ Z( Z# J+ S
1 * 9 = 9 meters
9 X1 }9 Q# N% V G5 t( lIf the pipe is vertical, The length of heat trace can be installed is about' s) Z u% {% ~% p
1 * 10 = 10 meters. ) }1 ~1 M( Z, |% X8 v
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
* A( S6 F9 ~4 h# xif the pipe is horizontal , The length of heat trace can be installed is about
: \2 ?. o3 H: }; v+ f, y: `1 * 4 = 4 meters4 [) ^% M7 _1 c6 t0 J/ E$ T/ R
If the pipe is vertical, The length of heat trace can be installed is about
, G" a, Z6 e* n& ?! J4 @1 * 5 = 5 meters. |
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