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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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1# jack_lai
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' `8 u1 Q* o( Z8 Y* o) f, J/ e" I. W足球看完了来看看题目。
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! B7 [% `7 P7 J/ }: U# t6 B1 ZThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
# T" l/ r- v, YThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different) p7 w. X5 D7 O- U9 p( P/ a$ ]# U
We can see it is not easy to install the 22 meters heat trace according as figure 14 ?" ]2 M D- U4 N4 n
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As a normal question we just discuss:6 v4 p% I: Z" W' a4 w9 v7 ~7 t$ X1 ^, v
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? ' s4 Y Y( j/ d& O% \+ l
I call this is JACK LAI Spiral Method 螺旋法 c Z! M, I$ R7 v8 `
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.1 w: {2 p' v. H+ [) {
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. % y6 H x* M$ W& m* ~
Because the pipe is horizontal, position 0 can not be placed. See figure 2* E# |) r8 L" F9 y+ j' S
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3+ g# |; N. F; N% e U" W6 n
The total heat trace that can be installed here is about
$ V! o* }" Q: Z+ |/ p ` c0 E7 f1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
9 M5 m% j+ ^9 k# dSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. ' w9 _' C9 `6 {8 M7 q0 n% o& X$ Z# g
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Note :
o# h6 a7 [& v* Q: f8 |% w1. The minimum bend radius:
0 ^7 ]* u% ~. p. A3 ?Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
4 [7 ~' l, {+ P% n4 {2 Y+ n5/16 *6 = 30/16 almost = 2 inches& S4 o8 n6 R w! {3 C3 `
So the maximum bend radius is 2 inches., P% w% }+ P2 L% |4 d% P
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3 Z6 f: q' I- o; iSummary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
: f8 Q/ [6 t, f: j" pif the pipe is horizontal, The length of heat trace can be installed is about+ P9 V4 C% W8 U* \( X+ a
1 * 9 = 9 meters8 N! |: p) ?0 y& f/ {
If the pipe is vertical, The length of heat trace can be installed is about
' X8 @# g, U/ |& @' O1 * 10 = 10 meters. 1 D, r$ {7 v, M$ f- j# m* }3 ]
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
/ p& o% `% D" F6 U3 P' Q; L5 o; g# Iif the pipe is horizontal , The length of heat trace can be installed is about
: y0 g4 x# x& D: n! V& }1 * 4 = 4 meters& G' `4 B$ e- i% T) o' R+ H) V
If the pipe is vertical, The length of heat trace can be installed is about" B5 ?3 W: h3 P* C' O; \, U
1 * 5 = 5 meters. |
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