 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 3 y. `8 w9 e) `! L0 C7 N) W& I
+ y* G( @" [" y' S
1# jack_lai
! f7 T u/ i0 b( N' a2 x: k. r) m+ |
足球看完了来看看题目。
- k- ~( e: W' D4 ]7 j' I* S- I0 S" G9 k( l, A# T R% x
The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
5 A6 N" A6 V8 L7 l* X0 B( v% rThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)( \+ U" N# R$ O0 z9 H6 N$ h3 @
We can see it is not easy to install the 22 meters heat trace according as figure 1
+ J& @5 m$ v) y& {; f1 @" J$ {5 K5 j
9 V7 i* d- l% Q
6 X$ X, l6 A& J3 P! U" {& f) w( ]) A; X% s
As a normal question we just discuss:, e8 _2 R( S9 S3 O( H/ [# X
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? & O- h- l2 Z3 V6 R3 n
I call this is JACK LAI Spiral Method 螺旋法
8 y' K0 ]1 G. xThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
7 ^0 h7 N2 B+ y7 pThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
z3 s7 Y% i! [! T X3 r- ZBecause the pipe is horizontal, position 0 can not be placed. See figure 2
% f% S% ^0 @# H, TBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 38 K5 u0 s g/ a, {
The total heat trace that can be installed here is about i) R2 w" j- o6 e8 T4 L+ f' |
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
. `' M* J2 q- vSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. ) I, f, N; n. @6 U& V
. w' j2 x, @- o5 H7 N" p5 @
Note :4 v, t* V! y8 C3 d. w1 z4 I
1. The minimum bend radius:
7 U, V& i2 W+ P1 _; ZBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is* d" U) F% s& K) t' T+ Q6 F2 n- H
5/16 *6 = 30/16 almost = 2 inches
2 o$ w' H1 b$ mSo the maximum bend radius is 2 inches.& a( d: n* X6 a: f3 w, \
# w s7 f1 L1 s( k
& J5 `+ l& `; J9 s4 D: t* ]
) m. D6 `: k+ e; m$ V+ D8 \Summary
6 w& x) W a7 c: f/ M5 x- L bAs regular 6 \5 { C e. K4 z6 X
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
?1 A( A8 \% Tif the pipe is horizontal, The length of heat trace can be installed is about
& J6 M% k$ O; f1 N2 t1 * 9 = 9 meters9 E0 k! q* p2 @6 [, ?& K1 n
If the pipe is vertical, The length of heat trace can be installed is about, f/ W5 A2 V k% n( t8 B' v
1 * 10 = 10 meters.
( R+ d6 N% f$ t2 dFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe( n6 m8 Q% L4 f. O y" H
if the pipe is horizontal , The length of heat trace can be installed is about
# Q/ P% }0 K1 @( i+ k {; p1 * 4 = 4 meters
2 G, ]4 F; o& s( m( OIf the pipe is vertical, The length of heat trace can be installed is about
9 H( t8 a: B5 v1 * 5 = 5 meters. |
|