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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 ' {; s0 I' P+ l* W, J+ Z
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足球看完了来看看题目。
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# E3 \5 M9 c# @9 z# E0 {% [; v' XThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
6 I# L$ I3 r! k' {2 I6 HThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
# ?% m2 M R# u8 j- x" w. \8 BWe can see it is not easy to install the 22 meters heat trace according as figure 1' F: O6 [& y) S' Z4 B
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! I% \# l8 j4 n% E kAs a normal question we just discuss:' D: a) z7 X; b7 O& P
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? / [; |) H& k h
I call this is JACK LAI Spiral Method 螺旋法9 G$ m. c( l1 W, Q) _. m$ t
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
/ u. d p' Y# v. o$ \There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 7 ?/ R: G8 {0 j/ r9 D
Because the pipe is horizontal, position 0 can not be placed. See figure 2# {; X) X1 E+ Z6 A! Z& Y, Y
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
]& j# z) A6 K4 M% O' J1 yThe total heat trace that can be installed here is about ; @: \6 R" T! s4 E) E8 Q+ y
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters& V9 k j3 E/ t. F
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. ( U: J$ @+ G& L* c* P' _
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Note :1 r* `& }$ r1 v2 I
1. The minimum bend radius:4 v* X6 q D$ p
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
/ _' K, Z1 ~8 S; B$ P* \5/16 *6 = 30/16 almost = 2 inches6 ~9 D; S# l3 w9 b4 G
So the maximum bend radius is 2 inches.0 ~9 \: _6 \5 l4 y
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* t; x$ I. w6 Q; R" t9 k9 aSummary
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9 R! E; a! } S7 p" V1 `For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
. w/ v9 J9 z+ A* c9 B6 rif the pipe is horizontal, The length of heat trace can be installed is about
( F3 L5 O& n+ I' w& H5 i1 * 9 = 9 meters
1 n+ ~4 i) ^4 f+ q7 IIf the pipe is vertical, The length of heat trace can be installed is about2 w, M& R# B2 p/ |' }& A2 F
1 * 10 = 10 meters.
' t9 U3 r1 t* DFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe# f5 W$ \5 E' R3 A
if the pipe is horizontal , The length of heat trace can be installed is about
2 e- z5 a8 o% ^9 d3 s- c0 R. `1 * 4 = 4 meters
) Y* L9 k% @4 D; J8 L! RIf the pipe is vertical, The length of heat trace can be installed is about
0 j% v' P$ k6 ]6 n' s/ Y1 * 5 = 5 meters. |
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