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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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1# jack_lai 5 I# J8 X3 j6 \/ T6 j
. r# h3 Y, m* s# n足球看完了来看看题目。
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3 u8 X, h1 L9 Q! W, \The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
9 G% J1 |- J8 M6 aThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
* ~# P- p d/ ZWe can see it is not easy to install the 22 meters heat trace according as figure 1
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As a normal question we just discuss:
; D) S% S% T8 m* sHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? $ _- f! }+ p* {+ g5 x. t/ q* l
I call this is JACK LAI Spiral Method 螺旋法3 Z" I9 M3 k- E9 {8 K6 V0 Q/ V
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
& j4 ?0 n; }! n+ Z& H/ p# oThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
' A9 \9 G/ I" {8 u3 }Because the pipe is horizontal, position 0 can not be placed. See figure 28 P$ u C; ]2 _* Q7 [) o4 r
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 32 }% x1 W4 k0 X* T1 }. O! _
The total heat trace that can be installed here is about $ U0 u% [# ^6 v0 U
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters0 S' u/ o( U8 I( M/ N$ n1 W( w
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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+ Y2 N& j+ o& e. f3 V2 K7 pNote :: y- [9 Q% @: ]0 c/ n
1. The minimum bend radius:' s; C/ Z) s& K/ J7 }+ r8 h+ h5 r+ a6 F
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
- U% X' x6 z5 z5/16 *6 = 30/16 almost = 2 inches3 C! D7 K6 y+ ?8 d) _- m& R
So the maximum bend radius is 2 inches.
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Summary" ~% ]8 ^& O! v7 G+ m
As regular
% x2 ~; I5 x( HFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
$ g* t5 S" d% S9 |8 ^ U- {7 Iif the pipe is horizontal, The length of heat trace can be installed is about
s1 m1 E+ Y: v7 R; l1 * 9 = 9 meters, u6 H1 x. s+ t5 f( t
If the pipe is vertical, The length of heat trace can be installed is about) d8 Z2 G* S6 l% G5 Q4 s
1 * 10 = 10 meters. + e' d: G9 }1 |+ j6 U
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe1 P3 R% W/ x) G
if the pipe is horizontal , The length of heat trace can be installed is about5 x" r6 x5 b4 ~- O2 o' V! c* }" l: [
1 * 4 = 4 meters
|& u- x, s3 O! RIf the pipe is vertical, The length of heat trace can be installed is about& Z% u, \, b: C
1 * 5 = 5 meters. |
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