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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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5 d" v' m- y- t 1# jack_lai 8 N' b7 G; ]# s& Z) _; J
$ S2 _/ P' x! _/ u, a2 w足球看完了来看看题目。0 g- U0 Y( _4 h9 A5 j
# }* J9 `/ I, _. E! YThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
" [$ z& b. O0 T8 {# |: G' lThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)) x5 i$ [% @+ ^
We can see it is not easy to install the 22 meters heat trace according as figure 1
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As a normal question we just discuss:, x4 P1 Y* O2 f9 F5 X! [- }2 N) s/ B
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? V, `# g2 Z" J! Y
I call this is JACK LAI Spiral Method 螺旋法/ r' \, W% k* l
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
; T: H2 A p7 \1 CThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
+ C: W7 ^+ t* gBecause the pipe is horizontal, position 0 can not be placed. See figure 2' _. \! k, o: C, c
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
4 |1 o& [# s+ j i) [8 PThe total heat trace that can be installed here is about
; \' d7 D( W( m' K# ?& m/ g8 d1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters1 O( ^) R3 U: T0 ^, f
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. - C5 ^0 G5 L6 _. I8 ^
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Note :* j3 E2 o A1 L) Q% g* C4 o: ]
1. The minimum bend radius:
W9 }4 d5 ]# I7 A6 r$ cBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
* t2 j6 A3 q" b2 s* |3 f4 U2 b5/16 *6 = 30/16 almost = 2 inches
6 W0 A4 o% A) F1 s5 T/ \ qSo the maximum bend radius is 2 inches.
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe0 A5 K0 D5 M6 y2 W: q3 N- H. O
if the pipe is horizontal, The length of heat trace can be installed is about- H( D$ }+ P) ^ ^' m
1 * 9 = 9 meters$ N1 X7 U7 @0 n: h6 X
If the pipe is vertical, The length of heat trace can be installed is about
/ T5 x e( }) F/ T. V1 * 10 = 10 meters.
" v5 d# W4 @ u% bFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
0 |* h$ U3 g- x( @. h1 p( J, Rif the pipe is horizontal , The length of heat trace can be installed is about
4 `0 @: j& T8 f2 |1 * 4 = 4 meters4 \* J# J4 J. Z9 Q2 q, R8 y2 m d
If the pipe is vertical, The length of heat trace can be installed is about
: o% l$ {5 s1 X/ N& _9 D: t1 * 5 = 5 meters. |
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