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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 & D% f$ w* f0 j, Q$ j: r
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1# jack_lai
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足球看完了来看看题目。0 a$ L& ^5 r: n, |
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)0 a1 J I- }: [6 i4 T& B
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)% ~0 G+ @) W0 n' q
We can see it is not easy to install the 22 meters heat trace according as figure 1, f: \8 H O6 d( ~
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$ h/ a$ S5 W! N1 `2 |9 nAs a normal question we just discuss:
7 l4 c* T( _ ]% {4 AHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 0 Q( [2 G8 l J. [$ r; e% p
I call this is JACK LAI Spiral Method 螺旋法* V' r! b* S9 x5 c# F8 [3 m
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
: Q7 n0 l6 b0 Z0 o1 qThere are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
s# _" x3 F" l9 f/ B, \5 DBecause the pipe is horizontal, position 0 can not be placed. See figure 21 Q% [7 w4 T a- U+ B; D
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
) m; M4 o1 V' n1 D7 u. s3 sThe total heat trace that can be installed here is about 3 ?2 c, F8 U0 i1 ] g0 y6 w( t. ?
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
. u% `! ?. x7 L4 J' KSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. 7 |5 z' r- J+ e" g6 z& r
4 I, [3 E" i xNote :) h5 O& a; G2 [, _
1. The minimum bend radius:
1 }8 S9 r4 L$ \5 v) d% wBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is" i5 Z$ E7 {+ M0 e
5/16 *6 = 30/16 almost = 2 inches' u b8 ~( t1 @4 W6 h
So the maximum bend radius is 2 inches.9 J% t4 ]2 P6 |6 z5 ]
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Summary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
0 r, l# w4 g8 v/ ^* `& ]" Zif the pipe is horizontal, The length of heat trace can be installed is about3 L4 H, c3 M N! ]0 E
1 * 9 = 9 meters
& y8 G- z/ d( P- d5 \. ?If the pipe is vertical, The length of heat trace can be installed is about) z, G/ m9 Q% N" a' I1 N4 X0 c
1 * 10 = 10 meters. $ k8 u/ X) p0 ^3 z2 k d+ W/ q, N
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
/ s7 R, {/ L2 A6 _+ H3 Q$ M4 p1 ?+ \if the pipe is horizontal , The length of heat trace can be installed is about
5 s# W/ d2 h% a: o# r6 N1 * 4 = 4 meters4 u+ ?' G* B3 ?7 w3 {0 C# O
If the pipe is vertical, The length of heat trace can be installed is about
/ e& ?8 o. X- g0 \1 * 5 = 5 meters. |
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