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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
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足球看完了来看看题目。- e7 P' O; `4 t' Q$ e. G+ ?0 Z/ V
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The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)8 Z% ]0 g& ?& o( x& p& V
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
6 |5 E; u! u6 W2 K% h4 \* ?We can see it is not easy to install the 22 meters heat trace according as figure 1% p$ c% V5 l* N2 m0 Q6 P
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As a normal question we just discuss:
, ~2 n h! [. b# t% w; l) hHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
! B# A4 d# E7 u6 Z. T& }0 M1 y" FI call this is JACK LAI Spiral Method 螺旋法7 o: p: j7 x0 d+ Z: ]/ _4 E* x
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.! b2 p# z' ]7 U5 L3 ?
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. 2 O' V6 A0 z; f8 f: p- K! H9 W( Y
Because the pipe is horizontal, position 0 can not be placed. See figure 2
# t9 V, n3 z) E. g4 | K& Y; cBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
( @! c4 O6 o: S% Y# cThe total heat trace that can be installed here is about 3 d( i2 f' B p5 @7 G i' G
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters* t- h! }3 [# g P4 l, f# k
So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
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( r. Y2 v' ?* G4 zNote :
2 Y- l2 S4 W. R8 w' w1 w9 F# S1. The minimum bend radius:1 H7 A: L) `7 y$ S2 y/ D; e
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
$ P1 m* _$ n$ x |6 t5/16 *6 = 30/16 almost = 2 inches
7 G) r0 {" A$ O5 J% _! n! RSo the maximum bend radius is 2 inches.3 G* W+ v8 Y/ [
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As regular
1 P' A8 O& Q( i% iFor 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
1 b2 Q1 o g) \) A. ]2 C0 i4 c1 I% [if the pipe is horizontal, The length of heat trace can be installed is about7 T, j' ]& j. O+ ?
1 * 9 = 9 meters
0 X' z; v* [& w1 r' N/ BIf the pipe is vertical, The length of heat trace can be installed is about: z _) r, R" [# b/ X6 _$ L+ C
1 * 10 = 10 meters. ! z0 Y" h5 _& p: Y
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
* U7 X& q {6 r1 Z' j7 kif the pipe is horizontal , The length of heat trace can be installed is about& A. V8 z M" T! w/ q" D
1 * 4 = 4 meters- h" f2 O/ w3 ]6 }% E
If the pipe is vertical, The length of heat trace can be installed is about
# V2 l# d* c. \; k# r1 * 5 = 5 meters. |
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