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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置
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0 `! X# U7 t' t7 E7 b4 R" A
5 Z6 S' s0 ?) G0 H+ o6 _) x5 c/ B8 B0 b9 ?- `3 t
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:& a" t" e0 @" K% k. o
- Z3 U& q1 |' b: E- G7 u! R' Fmz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.+ v0 u+ e/ y+ g" H$ V/ O2 i
2 p3 e' _& N/ [" S% a0 Y5 dCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).$ O- E. _( X; y n/ t5 ~
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