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All Numbers Are Equal
( D2 v7 p7 v$ a s# E5 vTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
, j, a+ {$ t4 L* a* k# H5 D t( D' M. o+ L
0 O% q2 v; u/ [% D! da + b = t
! E8 z" ^1 e2 q1 F- z(a + b)(a - b) = t(a - b)3 z) i( A) b0 \% D1 q
a^2 - b^2 = ta - tb
/ H/ A0 Z* d- ~a^2 - ta = b^2 - tb
$ d1 E w7 W: J( \a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4+ Z% v, K0 p8 q. j! o
(a - t/2)^2 = (b - t/2)^2
3 f1 \2 A: [" o8 j# B+ Z" qa - t/2 = b - t/2
, Y! [% k9 d* W: O Z; f1 C. ]a = b + O1 A& v# L9 z0 l
) ] M! ~ O& Q* {8 ~0 t/ \7 USo all numbers are the same, and math is pointless. |
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