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All Numbers Are Equal
2 P8 V8 a0 {5 FTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then ' x/ C+ F J; L+ c4 `- e) V
. c4 |1 p. [! i) e/ n) }
a + b = t
4 Y" y! C2 u T3 a- X; ~. h(a + b)(a - b) = t(a - b)3 I3 [3 M( v7 r$ I W0 L6 A, u: }4 j
a^2 - b^2 = ta - tb
' k6 ]5 F5 O, z% l z( s' Ya^2 - ta = b^2 - tb
) P1 T$ ?% a' p f; @a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4! L: n0 o, U) B; p- C6 f- `' {
(a - t/2)^2 = (b - t/2)^2! i6 h0 l# E o
a - t/2 = b - t/2
% n- X) F2 d/ p- S1 `6 n- E2 ?a = b
2 E- b F# |, a, I" F* c# r, \2 h% f6 A/ O+ m- n
So all numbers are the same, and math is pointless. |
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发表于 2006-6-13 09:17
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