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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置( Q5 d5 d# P* ? [& M" Q) e
$ G' K3 [: O. @+ B8 B' g) L7 z3 X' F" m8 _& s% O
: a. i4 s2 ]& l0 D+ P+ g(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:0 n( ?- v4 |4 m% g1 y+ L
6 M8 c4 K0 Q7 Z4 n% |mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2., x0 P% Q3 _5 ^; y% ^( \
" w* R# t5 v2 @. `* [Calculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).* N( A/ ^, e- I, u
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发表于 2012-4-2 21:27
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