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All Numbers Are Equal
( }8 z, e$ H0 P2 rTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then / Q* r/ Q% M9 c* y" g2 D4 W
7 z$ {3 ]( R2 W% V9 T* C9 a$ Ya + b = t
, k. ?) e7 n) G* ^. G% w6 Q; a(a + b)(a - b) = t(a - b)3 P% @* |+ C2 Y* Z7 w
a^2 - b^2 = ta - tb0 l _) n/ _: t3 F& O. E6 {
a^2 - ta = b^2 - tb
2 M9 @! f. X2 t1 qa^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/40 K7 K$ N2 y# L6 {# y& ^
(a - t/2)^2 = (b - t/2)^2' |; \4 D3 [* H' |
a - t/2 = b - t/21 k' K L- L7 @ r
a = b
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5 x- r) ]0 u' q+ N4 o% NSo all numbers are the same, and math is pointless. |
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