All Numbers Are Equal

我来也

All Numbers Are Equal   
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
, q9 {' I, B3 e; |
" [2 A, \/ Q3 `" ~a + b = t
) H+ t: {8 ?3 u, Y: \& k(a + b)(a - b) = t(a - b)
5 D, e7 H" [$ B, ~$ J( m" l. da^2 - b^2 = ta - tb
. ]% `( J- V' e& I, na^2 - ta = b^2 - tb
; M: Y* T) _! E! \, J* k+ K$ Sa^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
0 r  `4 B# n0 ^6 e3 v(a - t/2)^2 = (b - t/2)^2
+ O% w2 `# F7 ~% E7 K% d( m2 Oa - t/2 = b - t/2
a = b
0 t* ~( ?3 z- S$ ^& N
% x) H2 h" {  R+ XSo all numbers are the same, and math is pointless.

老V

朋友    你算错了    在检查一遍吧

我来也

原帖由 老V 于 2006-6-13 11:05 发表
! a8 e- E' i5 P+ d4 e' @朋友    你算错了    在检查一遍吧

高桥

does a^2=b^2 implies a=b? why not a=-b?

我来也

原帖由 高桥 于 2006-6-13 12:11 发表
; V8 _9 s! v, V! n6 g7 {+ Zdoes a^2=b^2 implies a=b? why not a=-b?

高桥

原帖由 我来也 于 2006-6-13 21:47 发表
3 m) H+ A8 W; T, |0 e% ]