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知道地球磁场的single dipole moment Mx, Mz,My如何求 相交的位置1 _2 R! u+ q$ I# w
/ R! `/ j8 ~: a; i; C |/ f+ \% ]2 d6 D# R- x
; ~: }& a# z" z" f6 w
(2) The Earth’s main magnetic field at the surface (radius = 6371 km) can be approximated by a single dipole moment at the Earth's centre with the following (x,y,z) components:# o+ X, Y2 {# Y0 u# |9 I
2 ]" J3 R7 R8 Z1 r4 x
mz = -7.7 x 1022 A m2, mx = -0.479 x 1022 A m2, my = 1.399 x 1022 A m2.
: p) Z( Z* B/ B# _7 Z, r' s/ f$ A
2 B' i1 Y/ v; |# m1 iCalculate the location (latitude, longitude) where the axis of this dipole field intersects the Earth's surface (i.e. where the magnetic field is locally purely vertical and upward).* h8 a! d$ i9 L$ J# R9 [0 c/ S
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