All Numbers Are Equal

我来也

All Numbers Are Equal   
. z) ^) a3 G! T0 A" KTheorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then
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a + b = t
(a + b)(a - b) = t(a - b)
7 K; E0 l, [1 G( v. `' I; @a^2 - b^2 = ta - tb
7 e# `, ]5 O' |7 k. p6 ]8 ea^2 - ta = b^2 - tb
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4
(a - t/2)^2 = (b - t/2)^2
  X& S$ |/ h% O, V8 A9 q# sa - t/2 = b - t/2
" o- S) e; T2 f, g7 d+ _/ Ma = b

4 \' c8 [/ [2 M* s+ ]( ySo all numbers are the same, and math is pointless.

老V

朋友    你算错了    在检查一遍吧

我来也

原帖由 老V 于 2006-6-13 11:05 发表
朋友    你算错了    在检查一遍吧

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高桥

does a^2=b^2 implies a=b? why not a=-b?

我来也

原帖由 高桥 于 2006-6-13 12:11 发表
2 A( [6 P  g4 ^5 m- b9 m7 B( Ndoes a^2=b^2 implies a=b? why not a=-b?

  R" x$ A% P- T9 C

高桥

原帖由 我来也 于 2006-6-13 21:47 发表
- t1 Z( h" u: A6 }2 e4 z7 P