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48 51 0 0 1 $ j- n1 @3 t( h: l( r- `" W/ r * M5 _8 r, r7 dIf #1 dead, #2 can get 50, that is the biggest number he can get. so give him 51 ( If #1 gives him only 50, what if #2 hates #1? then he can still get 50, but #1 is dead. ) 8 H6 m4 r% ^& j1 M4 h0 d: Q" n#5 very likly will get nothing. so give him 1 he would be happy.2 E4 ?; @8 a6 I. x9 e# S% q
#1 gets the rest of the 48.
Originally posted by 三思 at 2005-4-22 15:06: + ~. a3 O5 d8 v/ l7 P他会提出,他和第二个第三个人平分,不给最后两个人。因为 ) `. `5 q& [; { & n8 h/ T7 x% {- J他怎么分都会被后人否认(即便他自己一个不要),然后被处死,这样后面的人就可以多分。他死后,第二个第三个人面临同样的处境。 8 U2 g* a1 \0 [3 j+ W9 l" R5 ] P B: Y) ?" R
并且,他必须让两 ...
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OK, If I am the #2, I would not agree that, remember, if #1 dies, #2 and #2 each get 50, then that is half agreed, right? then #2 gets 50.
Originally posted by 人生无解 at 2005-10-1 10:54: ) G, I% i: v/ S! @: Z k' V4 a5 F% |1 2 3 4 5 . U- a, A) I% l0 D1 t: y48 51 0 0 15 E" K, K1 H$ W' W4 b
; k+ c, J/ d+ a+ T0 A: L% p# mIf #1 dead, #2 can get 50, that is the biggest number he can get. so give him 51 ( If #1 gives him only 50, what if #2 hates #1? then he ...
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' [, }; H3 }6 K& E/ v6 O$ por maybe I am wrong, what if #1 devide it to be 98 0 0 1 1??
我觉得对于一号来说最佳分配方案应该有以下3种,每一种一号都可以拿到98颗: / ^8 ?# b# N1 F3 M. X$ y- @" U, m(1)98-0-0-1-1( [' _% l( e" v
(2)98-0-1-0-16 K8 b6 V& c2 f; L7 D, w
(3)98-0-1-1-00 u2 I" c E/ A7 a q
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只要一号给余下除了2号以外的任意两人各分1颗,提案就会通过。- }1 P/ [8 a1 k3 Z. p