 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 * R$ ~. P2 J# J6 ]. ]! r$ m
) @* x" x. A/ \+ N 1# jack_lai
! H" `# D( A! b- U/ W3 H5 s V
! W( T( W0 J; S6 P2 g$ i3 [足球看完了来看看题目。; Y/ ?8 ^0 e! t8 R. @8 [7 K
* T6 N1 [+ h/ K+ h
The length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)7 M) h# K z' J* C+ K
The drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)0 G/ G/ ^, K: a$ s C! ^
We can see it is not easy to install the 22 meters heat trace according as figure 13 P+ v; s. m* @; c6 Y5 L
6 D1 m0 w2 @6 x; \5 g
0 n: |3 \) m( }/ J
5 j( e- r6 s& M8 Q
+ l, E! f8 S) N( ]5 ]; KAs a normal question we just discuss:) o( @9 O* B% ]/ M, ?0 ?& H2 S
How do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? 4 z! {5 o: `5 l, E5 \7 i
I call this is JACK LAI Spiral Method 螺旋法
8 B. H0 J* h6 r" I1 _" p: g! R7 I3 IThe outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.1 I' h8 ^8 p' ?
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
0 R6 O2 l! _" fBecause the pipe is horizontal, position 0 can not be placed. See figure 2
- b! e* r1 z) v) Y! s( T8 ZBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
5 }$ ]! Q; l; {# b( F/ S; w# x$ x& jThe total heat trace that can be installed here is about 2 E! F, u. v8 k1 p5 x* ]
1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
: M; B4 _( X" r' k, cSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. : o; ], A3 H K- ^
* _! O- u/ i, @' h9 ENote :
/ X" R! Q" Q; Y6 Q1 E2 J4 Z1. The minimum bend radius:
; m z0 |4 k% A9 z# t, S$ vBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is# h) v! @6 C) p
5/16 *6 = 30/16 almost = 2 inches8 d. |4 B: R' S4 Q: @: b; [0 c4 @2 I
So the maximum bend radius is 2 inches.- x/ k- t8 ~2 z7 g6 ~$ A3 f
F3 R5 Z) e$ m4 y$ _& _
. g6 E2 ?5 Y$ ~/ H/ {# w+ y K6 c: H* G
3 b S9 S. o4 @8 t: C$ D3 FSummary
5 G- N8 P- H( O% C) Z& n6 D( CAs regular
( J* k# k1 J" ]0 a L, Z% z$ A [For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
/ H1 Q6 t- l6 k) g& b: pif the pipe is horizontal, The length of heat trace can be installed is about, j% q: e! n2 A! D
1 * 9 = 9 meters; u( v( d, l% u0 f1 n! Z6 D: ]! Q9 H
If the pipe is vertical, The length of heat trace can be installed is about) A4 Z& P- r4 T3 h* z
1 * 10 = 10 meters.
2 f8 n" V9 {5 |For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe6 X) F& }0 P2 F8 y. M8 m E; I" p3 R
if the pipe is horizontal , The length of heat trace can be installed is about
0 Q+ M6 l+ K- m0 e# E1 * 4 = 4 meters
) {$ J, }: P6 D$ t5 N: F e$ X& xIf the pipe is vertical, The length of heat trace can be installed is about+ {/ k Z& S' e9 z& I+ k
1 * 5 = 5 meters. |
|