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发表于 2010-7-10 17:18
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本帖最后由 jack_lai 于 2010-7-10 18:52 编辑 7 W! k' m, o6 o6 z
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足球看完了来看看题目。9 w$ [6 B- q" W. r* r
! Y, P1 ~: n& D( z0 |9 A: n( S5 U0 E! `5 sThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
0 ~- V6 E- @# q7 z1 S/ yThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different)
$ c) Y7 A3 \7 W3 bWe can see it is not easy to install the 22 meters heat trace according as figure 1* r( O" M0 b! ?
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As a normal question we just discuss:
* `/ |8 d: s2 F V& fHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ? " B1 H+ \2 k8 r% c2 W4 A
I call this is JACK LAI Spiral Method 螺旋法3 V* F: e. Y0 m, n7 K5 z8 C
The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.
+ V* I1 ]; I3 u; E" `There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch. + B; J w" K2 Z& }2 ^1 r" W( x
Because the pipe is horizontal, position 0 can not be placed. See figure 2
" ?+ q, E; r7 g* o0 X* cBecause the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 30 K5 m1 j9 V; R3 N% C
The total heat trace that can be installed here is about
0 [! m2 L1 ~1 m1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
9 K N7 i' [! L* l, ?So, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem. " G3 z/ B9 R0 L1 i2 i: P
0 K# F' o. K u- T5 w, Z+ jNote :
2 F2 E7 l9 H6 q4 |) ~1 |2 N$ S1. The minimum bend radius:7 ~: } `) @ o6 w, _- ^
Because the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is4 @7 a6 I7 c+ D( x
5/16 *6 = 30/16 almost = 2 inches
! G8 I$ [7 s" M; |$ X% F' cSo the maximum bend radius is 2 inches.
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3 w8 \0 d' E& WSummary
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For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe% g& Q5 a" y; C& E) Y
if the pipe is horizontal, The length of heat trace can be installed is about
/ o$ j0 V, S% n1 * 9 = 9 meters8 j/ `6 v1 i( C0 l i' A
If the pipe is vertical, The length of heat trace can be installed is about
. e2 W5 g( A4 X1 * 10 = 10 meters. ( s% ?$ i% ^/ I+ t
For 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
7 K4 `2 I0 I& z) T/ ^if the pipe is horizontal , The length of heat trace can be installed is about( t4 o1 o$ W/ E( `1 b) b
1 * 4 = 4 meters
( V; L. \2 c: b8 H, ?If the pipe is vertical, The length of heat trace can be installed is about
4 p: X5 O3 v0 o1 O% a3 ]/ u* E" F1 * 5 = 5 meters. |
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