 鲜花( 0)  鸡蛋( 0)
|

楼主 |
发表于 2010-7-10 17:18
|
显示全部楼层
本帖最后由 jack_lai 于 2010-7-10 18:52 编辑
, C9 g3 b+ [' \4 k2 y Y! v7 S6 j1 H. g2 d' S
1# jack_lai
9 P5 K+ b7 D- `% N
/ K# g+ `; i& G3 S% M7 a足球看完了来看看题目。
2 ^) n7 L) D( B9 n$ K. n
6 ~) z& V( V# R: IThe length of the heat trace is 22 meters. The size of the heat trace is 5/16 inch (WATTS/ m SUPPLIIED is 43.7)
2 N% z6 a6 L& b" a8 mThe drawing is shown as figure 1. (All data is from the memory. They are not the same as the real drawing, but a little bit different): i0 {; U9 R0 h, _4 M
We can see it is not easy to install the 22 meters heat trace according as figure 1
7 G, S" C( C8 ]7 L6 }- D$ C5 P4 w
' w3 d6 K% d% o5 y' G8 Q. a+ }* o
# x% \3 [' N; L" c' k4 _+ C" {
4 S: |7 N+ M' M1 t: u l6 o" V* a& x3 G: W7 R- f
As a normal question we just discuss:
: ]5 F2 u1 q, D @6 C" g0 HHow do you run these 9.4 meters heat trace (size 5/16 inch) on the 3 inches 1.4 meters pipe ?
6 [: n/ `* y. b3 c: Z: _$ G2 Z" hI call this is JACK LAI Spiral Method 螺旋法
) k4 f- u* z8 W7 Y* ~The outside circumference of the 3 inch pipe is more than 10 inches. See figure 2.! ^8 [! c4 h& ^
There are 10 positions to plac the heat trace. They are 0.1,2,3,,,,,9. The distance between each position--heat trace is about one inch.
% o G7 B) G# @5 R% nBecause the pipe is horizontal, position 0 can not be placed. See figure 2) a/ J6 b* z$ ?" t' ?
Because the maximum bend radius of the heat trace is 2 inches( see note 1), position 5 can not be placed. See figure 2. Then the route of the heat trace can be like figure 3
% V, {; |% U `6 I" S- h* AThe total heat trace that can be installed here is about
' ?/ `( L6 S- J& a1.4 * 6 + 1 * 2 = 8.6 + 2 =10.8 Meters
, }3 j* Q( v: A$ z% H4 eSo, the 9.4 meters heat trace can be installed along the 3 inched 1.4 meters pipe without a problem.
# U2 j5 z! ?! j2 r* X! s3 F j/ l+ d; U7 _9 _
Note :
* G- R- p8 k( Y+ G7 R: b1. The minimum bend radius:
3 Q1 G' _# B6 ?6 t/ T) s- ZBecause the heat trace size here is 5/16, 6 times the outside diameter of the heat trace is
% S: l& S/ R9 D* ?0 ^* V5/16 *6 = 30/16 almost = 2 inches1 ~& W: v9 n/ d# S4 C
So the maximum bend radius is 2 inches.- k$ A0 M) ^2 [; @3 G) H
1 R( ?1 {' V% h, G4 X, J/ q f" }
) D1 @: u5 k: d/ B ?- ^
4 y2 ~% X' w: v' {6 ]( k% V1 I0 d
Summary \; V% n; J6 S
As regular , s6 W# I8 U. K
For 3 inch pip: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe7 o$ ?5 h6 u2 b% _* p# G
if the pipe is horizontal, The length of heat trace can be installed is about
, g% }7 M3 }. i; `4 K* L" G1 * 9 = 9 meters
$ u; D0 \+ L% z* J9 q5 P$ b' sIf the pipe is vertical, The length of heat trace can be installed is about/ z* s* @- c P& o" P
1 * 10 = 10 meters.
: \3 m: c2 E8 A5 aFor 2 inch pipe: If heat trace size is 5/16 inch, and no RTD, the box position is close to the end of pipe. 1 meter long pipe
/ B+ X k& |" Y' t1 D7 S+ iif the pipe is horizontal , The length of heat trace can be installed is about
! O9 ?; \3 H( E) u1 * 4 = 4 meters; }. s( L) N. v# w7 u! ?: O
If the pipe is vertical, The length of heat trace can be installed is about
& l0 F6 @' T- x3 u1 * 5 = 5 meters. |
|