All Numbers Are Equal 6 o- F8 f* d; Z
Theorem: All numbers are equal. Proof: Choose arbitrary a and b, and let t = a + b. Then 7 l( r) H1 s; P: l4 u2 e2 ?' Z) }2 G
1 x. b- u# R- e% U7 [- c! [
a + b = t T; D4 q# _& r+ l(a + b)(a - b) = t(a - b) ' d. m% K# n; l/ oa^2 - b^2 = ta - tb* N, X$ I7 u f. w' |
a^2 - ta = b^2 - tb8 p. ~0 j* R0 n% V- L8 z. c$ c ]+ U
a^2 - ta + (t^2)/4 = b^2 - tb + (t^2)/4. a, o$ g3 Q! }- I) _ Q
(a - t/2)^2 = (b - t/2)^2% ^' L& m% A0 d& [
a - t/2 = b - t/2 5 v; x* l* y( a' w$ b: M) Ha = b 6 V0 i& z) f+ f% X% ^
: h e7 ^1 s9 k: { Y: E6 I" T; s
So all numbers are the same, and math is pointless.
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发表于 2006-6-13 09:17
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